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struts2.1.8+json+jquery1.3实现ajax

阅读更多

 

要加的struts包有:

commons-beanutils-1.7.0.jar

commons-chain-1.2.jar

commons-collections-3.2.jar

commons-digester-2.0.jar

commons-fileupload-1.2.1.jar

commons-io-1.3.2.jar

commons-lang-2.3.jar

commons-logging-1.0.4.jar

commons-validator-1.3.1.jar

ezmorph-1.0.3.jar      (不这个会去一非常怪错误。不相信你可以试试)  我认为应该无法实现java对象与json对象之间转化.

freemarker-2.3.15.jar

json-lib-2.1.jar

ognl-2.7.3.jar

struts2-json-plugin-2.1.8.1.jar

xwork-core-2.1.6.jar

struts2-core-2.1.8.1.jar

其它具体 的代码;我是看了。http://www.iteye.com/topic/576513。他是原码而写的。基本一样了。

web.xml

<filter>  
        <filter-name>struts2</filter-name>  
        <filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>  
    </filter>  
    <filter-mapping>  
        <filter-name>struts2</filter-name>  
        <url-pattern>/*</url-pattern>  
    </filter-mapping> 

 

strust.xml

 

<package name="ajax" extends="json-default">
		<action name="ajaxLogin" class="org.test.action.AjaxLoginAction">
			<!-- 返回类型为json 在json-default中定义 -->
			<result type="json">
				<!-- root的值对应要返回的值的属性 -->
				<!-- 这里的result值即是 对应action中的 result -->
				<param name="root">result</param>
			</result>
			
		</action>
	</package>

 

action代码:

 

private String result;
	// struts的属性驱动模式,自动填充页面的属性到这里
	private String loginName;
	private String password;

	public String getResult() {
		return result;
	}


	public void setResult(String result) {
		this.result = result;
	}


	public String getLoginName() {
		return loginName;
	}


	public void setLoginName(String loginName) {
		this.loginName = loginName;
	}


	public String getPassword() {
		return password;
	}


	public void setPassword(String password) {
		this.password = password;
	}


	@Override
	public String execute() {

		try{
			System.out.println("------------");
			// 用一个Map做例子
			Map<String, String> map = new HashMap<String, String>();
	        System.out.println(this.loginName);
			// 为map添加一条数据,记录一下页面传过来loginName
			map.put("name", this.loginName);
			map.put("password",this.password);

			// 将要返回的map对象进行json处理
			JSONObject jo = JSONObject.fromObject(map);
			System.out.println("*********");
			// 调用json对象的toString方法转换为字符串然后赋值给result
			this.result = jo.toString();

			// 可以测试一下result
			System.out.println(this.result);
			
		}catch(Exception e){
			System.out.println(e);
		}
		

		return SUCCESS;

	}

 

index.jsp

<%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%>
<%@ taglib prefix="s" uri="/struts-tags" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
	<head>
		<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
		<script type="text/javascript" src="js/jquery-1.3.2.min.js"></script><script type="text/javascript">
		$(document).ready( function() {
		//使用 Ajax 的方式 判断登录
		$("#btn_login").click( function() {
			var url = 'ajaxLogin.action';
			//获取表单值,并以json的数据形式保存到params中
			var params = {
				loginName:$("#loginName").val(),
				password:$("#password").val()
				//上行结尾决对不加逗号(,)。如果加了在IE6下就不能运行实现了。
			}
			alert(params.loginName);
			//使用$.post方式	
			$.post(
				url,		//服务器要接受的url
				params,		//传递的参数		
				function cbf(data){	//服务器返回后执行的函数 参数 data保存的就是服务器发送到客户端的数据
					//alert(data);
					var member = eval("("+data+")");	//包数据解析为json 格式  
					$('#result').html("欢迎您:  "+member.name+"<br>您的密码是:"+member.password);
				}, 
			   'json'	//数据传递的类型  json
			);
		});
	});
</script>
	</head>
	<body>
		<center>
		<table>
		<tr>
		<td>
		<span>用户名:</span>
		</td>
		<td>
		<input type="text" id="loginName" name="loginName">
		</td>
		</tr>
		<tr>
		<td>
		<span>密码:</span>
		</td>
		<td>
		<input type="password" name="password" id="password">
		</td>
		</tr>
		<tr>
		<td colspan="2">
		<input type="button" id="btn_login" value="Login" />
		</td>
		</tr>
		</table>
		<p>
			这里显示ajax信息:
			<br />
			<span id="result"></span>
		</p>
		</center>

		
	</body>
</html>

 

 

源码:

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评论
8 楼 伊然01 2011-05-24  
7 楼 skyjun 2011-04-11  
2011-4-11 11:59:36 com.opensymphony.xwork2.util.logging.commons.CommonsLogger warn
警告: Could not find action or result
There is no Action mapped for namespace / and action name ajaxLogin. - [unknown location]
at com.opensymphony.xwork2.DefaultActionProxy.prepare(DefaultActionProxy.java:178)
at org.apache.struts2.impl.StrutsActionProxy.prepare(StrutsActionProxy.java:61)
at org.apache.struts2.impl.StrutsActionProxyFactory.createActionProxy(StrutsActionProxyFactory.java:39)
at com.opensymphony.xwork2.DefaultActionProxyFactory.createActionProxy(DefaultActionProxyFactory.java:47)
at org.apache.struts2.dispatcher.Dispatcher.serviceAction(Dispatcher.java:478)
at org.apache.struts2.dispatcher.FilterDispatcher.doFilter(FilterDispatcher.java:395)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:235)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:228)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:175)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:128)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:104)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:216)
at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:844)
at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:634)
at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:445)
at java.lang.Thread.run(Unknown Source)
6 楼 itpentiuman 2011-03-22  
哥们多谢,例子很简单管用,注释也写得详细!
5 楼 chenandzoff 2011-02-23  
例子不错 谢谢
4 楼 pxh666 2010-08-19  
3 楼 lasimmm 2010-08-14  
谢谢。。。
2 楼 wojingwu 2010-08-02  
  
1 楼 水木清华77 2010-07-30  

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